this post was submitted on 09 Nov 2023
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[–] [email protected] 21 points 1 year ago (4 children)

Here's one for adults:

0.9• = 1

[–] [email protected] 13 points 1 year ago

For anybody curious, in another notation it's 0.(9)

[–] [email protected] 6 points 1 year ago (1 children)

That only works if you have enough nines.

[–] [email protected] 18 points 1 year ago (1 children)

That's literally what the dot means. Infinite nines.

[–] [email protected] 13 points 1 year ago (1 children)
[–] [email protected] 16 points 1 year ago (1 children)

There is actually a global scarcity of 9's but about 80 percent of the world's 9's are stockpiled in Nevada

[–] [email protected] 8 points 1 year ago

Well that won't do. I'll see about sourcing some 6's and a spatula to flip them.

[–] [email protected] 3 points 1 year ago* (last edited 1 year ago) (3 children)
[–] [email protected] 5 points 1 year ago* (last edited 1 year ago) (1 children)

might be missing a +1 (edit: it's fixed now)

[–] [email protected] 1 points 1 year ago
[–] [email protected] 3 points 1 year ago

Well e^iπ=cosπ+isinπ=-1 but an error of 1 isn't so bad so it's close enough

[–] [email protected] 1 points 1 year ago

That one always fucked me up in my calculus classes

[–] [email protected] -2 points 1 year ago (1 children)
[–] [email protected] 0 points 1 year ago (3 children)

Not really.

1/3 = 0.3•

1/3 + 1/3 + 1/3 = 0.3• + 0.3• + 0.3•

3/3 = 0.9•

1 = 0.9•

And that's only one proof, there are others.

[–] [email protected] 8 points 1 year ago

This is not a proof as you start with the answer, albeit disguised as a known truth. Here is a real proof. Start by assigning the recurring decimal a variable.

x = 0.9999...

Now calculate 10 times this by shifting the decimal place.

10x = 9.9999...

You can then subtract the second equation from the first. Note that all the digits after the decimal cancel out, leaving us with the following.

9x = 9
x = 1

Therefore, 0.9999... = 1. Infinity does weird things!

[–] [email protected] 2 points 1 year ago (2 children)

can 0.3• + 0.3• + 0.3• be really be added to equal 0.9• the same way that 0.3 + 0.3 + 0.3 = 0.9 though? and if so, is it proven or assumed? im not saying ur wrong btw, just asking. and does 0.000...001 equal 0?

[–] [email protected] 2 points 1 year ago* (last edited 1 year ago) (1 children)

0.3• has infinte decimals, 0.0000...001 does not. No matter how many zeroes you put before the one, there will never be infinite zeroes, so it's not equal to 0.

You simply cannot have "Infinity + 1" decimals, since infinity + 1 = infinity.

[–] [email protected] 2 points 1 year ago

okay...i dont understand but ill trust you

[–] [email protected] 1 points 1 year ago

There is actually a smallest number, typically denoted by a lower case epsilon, which is infintesimally small, typically used in calculus proofs.

[–] [email protected] 1 points 1 year ago (2 children)

I’m not a math person at all, so I’m not really debating your proof, but it seems to me that if 0.9• = 1, then what does 0.1• equal? It “fits” perfectly into the “space” between 0.9• and 1, but if 0.9•=1 then 0.1• should equal 0, right? Except it doesn’t, because 0.1<0.1• and 0.1 definitely isn’t 0.

I definitely understand why some religious people think numbers are a tool of Satan.

[–] [email protected] 2 points 1 year ago

It's infinite ones - as you expand it, the illusion offered by the single digit disappears. 0.999 + 0.111 is 1.11, so 0.999... + 0.111... is 1.111....

[–] [email protected] 2 points 1 year ago (1 children)

0.1111... is equal to 1/9. 0.0000... is trivially equal to 0.

[–] [email protected] 1 points 1 year ago (1 children)

My calculator agrees with you but it still doesn’t make intuitive sense to my brain. 0.1• still seems like it “fits” neatly into 0.9• to create 1.

Ah, well. Good thing I’m not designing bridges, right?

[–] [email protected] 2 points 1 year ago

Think of it with fewer digits.
If we have 0.999 and 0.111, then yeah, each 1 neatly complements each 9. But you have to consider that each of them result in a 1 the next digit upwards (as 09 + 01 = 10). So 0.999 + 0.111 equals 1.110. What you actually want here is 0.001, which just complements the last 9, which returns a 1 for the next 9, which returns a 1 for the next 9 and so on. 0.999 + 0.001 = 1.000. If you increase the digits, the zeros between the decimal point and the one increase too, causing the number to get smaller and smaller. If continue this infinitely long, the number becomes 0.

0.999• + 0.000• = 1.000•