this post was submitted on 07 Dec 2023
533 points (87.7% liked)

Asklemmy

43397 readers
679 users here now

A loosely moderated place to ask open-ended questions

Search asklemmy ๐Ÿ”

If your post meets the following criteria, it's welcome here!

  1. Open-ended question
  2. Not offensive: at this point, we do not have the bandwidth to moderate overtly political discussions. Assume best intent and be excellent to each other.
  3. Not regarding using or support for Lemmy: context, see the list of support communities and tools for finding communities below
  4. Not ad nauseam inducing: please make sure it is a question that would be new to most members
  5. An actual topic of discussion

Looking for support?

Looking for a community?

~Icon~ ~by~ ~@Double_[email protected]~

founded 5 years ago
MODERATORS
 
you are viewing a single comment's thread
view the rest of the comments
[โ€“] [email protected] 4 points 9 months ago* (last edited 9 months ago) (1 children)

Only if Monty Hall didn't know where the prize is

Say there are 100 doors, you choose one, then 98 are knocked out randomly (likely including the prize) - Now each of the 2 doors has the same chance of winning, so there is no reason to change

But starting with 100 doors and a knowledgeable Monty Hall, once you've chosen a door, the only reason Monty Hall leaves your door alone is because you chose it, whether it is the 1/100 winner, or one of the 99/100 losers

Either you chose the right door the first time (1/100 chance) or the other door has the prize behind it - those are the only options - the other door literally represents the 99/100 other doors in a single choice

[โ€“] [email protected] 2 points 9 months ago (1 children)

There's a flaw in this problem, which is the fact Monty Hall didn't consider the possibility I may have a gun pointed to his head

[โ€“] [email protected] 5 points 9 months ago

Do you have a Monty Hall problem, or does Monty Hall have a you problem?