this post was submitted on 27 Apr 2025
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[–] [email protected] 7 points 1 day ago* (last edited 1 day ago)

By the way guys, a very similar approximation for 8, which also starts at 9.000 for n=1, but quickly gets much closer to 8 for increasing n, is:

exp{-2(n-1)} + 8

It approaches 8 about as fast as the above method but this one has a simple formula that is usable in python etc.