this post was submitted on 24 Aug 2024
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No Stupid Questions
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Yes.
QC negotiation works by changing the voltage. This communication would be broken if you plug several devices to 1 charging port.
So you better get a charger with several ports where each port is capable of delivering QC / PD. They have independent communication then, and each device gets it's proper voltage.
That's assuming this cable forwards PD signals at all.
That would actually be the safer scenario, as a failure in the PD handshake simply defaults to 5v which every USB device can accept. It would be more dangerous to only have the PD negotiation be on one of the three ports, because then you could potentially burn out devices on the other two by sending them too much voltage.
I guess the best case scenario would be to have the PD signal run on all three, then default to low voltage if any of them fail. But that's likely not what they're doing, because then things would only fast charge if all three ports are plugged into fast charge devices. Because an unplugged tail would likely register as a failed PD handshake.
No. In QC it is the main voltage that is changed. No extra signal lines.
USB-PD changes thr main voltage in response to a handshake protocol on the C1 and C2 data lines, which this cable likely doesn't connect for precisely this reason. Qualcomm QC still uses D+ and D- to negotiate the higher voltage, which this cable likely wouldn't connect either.