this post was submitted on 15 Aug 2024
7 points (88.9% liked)
Ask Electronics
3315 readers
1 users here now
For questions about component-level electronic circuits, tools and equipment.
Rules
1: Be nice.
2: Be on-topic (eg: Electronic, not electrical).
3: No commercial stuff, buying, selling or valuations.
4: Be safe.
founded 1 year ago
MODERATORS
you are viewing a single comment's thread
view the rest of the comments
view the rest of the comments
From a cursory read of the datasheet, using the "dead time control" pin seems to be the way to go. Basically, this pin is used to set the voltage, while the error amplifier inputs (that's the closest function to "over current protection" this chip has) are used to adjust the output according to the load. For your application, you probably don't need to use them at all.
My instinct would be to disable the error amplifiers by connecting pins 1,2,15 and 16 to GND. You can then connect the wiper pin of the potentiometer to the deadtime control input, with the other pins of the potentiometer connected to GND and 3.3 V.
I haven't worked with this chip before, so take this with a grain of salt. You should probably use a simulation tool to check the circuit before you start destroying chips.
Thanks. Yeah you're recommending what I was initially thinking.
Fair!