this post was submitted on 17 Jul 2024
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[–] [email protected] 83 points 4 months ago (30 children)

That's not how it's works. Being "infinite" is not enough, the number 1.110100100010000... is "infinite", without repeating patterns and dosen't have other digits that 1 or 0.

[–] [email protected] 8 points 4 months ago (12 children)

If it's infinite without repeating patterns then it just contain all patterns, no? Eh i guess that's not how that works, is it? Half of all patterns is still infinity.

[–] [email protected] 24 points 4 months ago (10 children)

No. 1011001110001111... (One 1, one 0, two 1s, two zeros....) Doesn't contain repeating patterns. It also doesn't contain any patterns with '2' in it.

But pi is believed to be normal. https://en.m.wikipedia.org/wiki/Normal_number

So it should contain all finite patterns an infinite number of times.

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